Calculate ,efectuand mai întâi operațiile din paranteza rotundă :
(125+56+78)x0
202+202:2-202x(1-1)
(84-8x8):5(3x6:2+7x5)
693+600:0-(50:2+2)x0
(250+760:5)x19-120:4
Răspunsuri la întrebare
2024-05-06 09:24:20
(125+56+78) x 0 = 0 202+202:2-202 x (1-1) = 202+101-202 x 0 = 303-202 x 0=101 x 0 = 0 (84-8 x 8):5 x (3 x 6:2+7 x 5)=(84-64):5 x (9+35) =20:5 x 44= 4 x 44= 176 693+600:0-(50:2+2) x 0=693+0-27=693-27= 566 (250+760:5) x 19-120:4=(250+152) x 19- 30= 402 x 19 - 30= 8208
2024-05-06 09:25:35
(1. (125+56+78) x 0 (181+78) x 0 259x0 = 0 2. 202 +202 : 2 - 202 x ( 1-1) 202+202:2-202x0 202+101-202x0 303-202x0 101x0= 0 3. ( 84 - 8x8 ) : 5 x ( 3x6:2+7x5) ( 84- 64) : 5 x ( 9 +35) 20:5 x 44 4x44=176 4. 693+600:0-(50:2+2) x 0=693+0-27=693-27= 566 5.(250+760:5)x19-120:4 ( 250 +152) x 19 -30 402 x19 - 30 = 8208
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