Din 450 g solutie de acid sulfuric 40% si 150 g de apa se obtine o solutie de concentratie 3.75M.Indicati afirmatiile false cu privire la solutia obtinuta. A. Contine 180 g de solvat; B. Contine 420 g de solvent; C. Are volumul de 700 ml; D. Are concentratia procentuala de 35%; E. Are densitatea 1.8 g/cm3. SOLUTIA I    + m apa --------------:> SOLUTIA II ms1=450g          150 g                   ms2= ms1 +m apa  c1=40%                                          Cm= 3,75 molar  md1                                               md2=md1 md1=ms1*c1/100=450*40/100=180 g   m solvat                A. ms2=450+150=600 g m solvent= 600g- 180 g=420 g                                          B. C.   CM = n/Vs =====> Vs = n/CM   Vs = m/M*CM = 180/98*3,75 =0,489 l  (489ml) D.  c2= md2*100/ms2=180*100/600=30% E.  Vs=489ml,  ms=600g ===>   p=m/Vs=600g/ 489 ml=1,22g/ml